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Q.

Reaction rate between two substances A and B is expressed as following :

 rate =k[A]n[B]m

If the concentration of A is doubled and concentration of B is made half of initial concentration, the ratio of the new rate to the earlier rate will be:

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a

12(m+n)

b

n - m

c

m + n

d

2(nm)

answer is D.

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Detailed Solution

 Rate 1=k[A]n[B]m Rate 2=k[2A]n12Bm Rate 2 Rate 1=k[2A]n12Bmk[A]n[B]m=(2)n12m=2n(2)m=2nm

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