Q.

Rearrange the following (I to IV) in the order of increasing masses:
(I) 0.5 mole of O3
(II) 0.5 gm atom of oxygen
(III) 3.011x1023 molecules of O2
(IV) 5.6 litre of CO, at 1 atm and 273 K

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a

II<IV<III<I

b

II<I<IV<III

c

IV<II<III<I

d

I<II<III<IV

answer is A.

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Detailed Solution

(I) 0.5 mole O =  24 g O3;
(II) 0.5 g atom of oxygen = 8 g
(III3.011×10236.022×1023×32=16gO2
(IV)5.622.4×44gCO2=11gCO2

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