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Reduce the fractions to their lowest term using the HCF method:
a)      $\frac{24}{48}$
b)      $\frac{42}{63}$
c)      $\frac{15}{27}$

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\frac{5}{3}, \frac{9}{3}, \frac{3}{2}

\frac{1}{2}, \frac{2}{3}, \frac{5}{9}

\frac{2}{1}, \frac{3}{2}, \frac{9}{5}

\frac{9}{5}, \frac{7}{2}, \frac{1}{2}

answer is B.

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Detailed Solution

${"mathml":"<math class="image_resized" style="width:156px;height:222px"> <span style="font-family:$ ∴ The lowest term of

\frac{24}{48}

\frac{1}{2}

.
${"mathml":"<math class="image_resized" style="width:104px;height:304px"> <span style="font-family:$ ∴ The lowest term of

\frac{42}{63}

\frac{2}{3}

.
${"mathml":"<math class="image_resized" style="width:100px;height:224px"> <span style="font-family:$ ∴ The lowest term of

\frac{15}{27}

\frac{5}{9}

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Reduce the fractions to their lowest term using the HCF method:a) 2448b) 4263c) 1527