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Q.

Reduction of ${BCl}_{3}$ with lithium aluminium hydride gives

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a

Borazole

b

All

c

Diborane

d

Borazine

answer is C.

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Detailed Solution

${LiAlH}_{4} + {BCl}_{3} \to B_{2} H_{6} + LiCl + {AlCl}_{3}$

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