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Reena is twice as old as Suneeta . Three years ago she was three times as old as Suneeta. The present age of Reena is:

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answer is D.

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Detailed Solution

Concept- Assuming the age of Suneeta as a variable and hence find the age of Reena in terms of that variable. We will find the equations according to the given conditions in the question.
Let the present age of Suneeta be

x

years old.
Given, Reena is twice as old as Suneeta,
Therefore, Reena becomes

2 x

years old if Suneeta is of

x

years old, i.e.
The present age of Reena

= 2 x

years old
The present age of Suneeta

= x

years old
Now, according to the given condition in the question,i.e. 3 years age, Reena was as old as Suneeta, we get
The age of Reena 3 years old

= (2 x - 3)

years
The age of Suneeta 3 years old

= (x - 3)

years
According to the condition,

\Rightarrow 2 x - 3 = 3 (x - 3)

\Rightarrow 2 x - 3 = 3 x - 9

\Rightarrow 2 x = 3 x - 9 + 3

\Rightarrow 2 x = 3 x - 6

\Rightarrow - x = - 6

\Rightarrow x = 6

The present age of Suneeta is 6 years old.
Therefore, the present age of Reena becomes:

\Rightarrow 2 x = 2 \times 6 = 12 years old

Hence, the correct answer is option 4.

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