Refer the below given figure and identify A to E
 

	A	B	C	D	E
(1)	Mitosis	2n	Meiosis I	n	n
(2)	Meiosis I	2n	Meiosis II	n	n
(3)	Meiosis II	n	Meiosis I	n	n
(4)	Meiosis I	n	Meiosis II	n	n

According to given question, it shows the reductional division of a cell.
A $\to$ Meiosis I, B-n, C$\to$ Meiosis II, D and E$\to$n
This happen because after meiosis I itself the number of chromosomes are halves. Meiosis II is considered as equational division.