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Refer to the diagram one kg block performs vertical harmonic oscillations with amplitude 1.6 cm and frequency 25 rad $s^{- 1}$ . The maximum value of the force that the system exerts on the surface is $(g = 10 m / s^{2})$

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40 N

20 N

30 N

60 N

answer is D.

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Detailed Solution

Weight = 5x 10N = 50 N

Maximum restoring force $m ω^{2} A = 1 \times 25^{2} \times 1.6 \times 10^{- 2} = 10$

Maximum force on the surface = (50 + 10) N = 60 N.

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