Regarding E₁cb

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It takes place in the presence of a base

It is applicable to poor leaving groups containing EWG at $β$ -carbon

Carbon ion is intermediate

All are correct

answer is D.

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Detailed Solution

E₁cb reaction i.e, elimination unimolecular conjugate base reaction proceeds by two step mechanism. First, the proton is abstracted to form the conjugate base. Then, the leaving group leaves the substrate to form an alkene. The reaction proceeds through the conjugate base of the starting material.

In E₁cb reaction the compound must have an acidic hydrogen on its β carbon and a relatively poor leaving group on the α carbon.
The base abstracts the β - proton and generates negative charge on the carbon atom to form carbanion.

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