Regarding phenol the correct statement $$areA)$$ It reacts with $$Br2/CS2$$ to give a mixture of $$o-bromophenol$$ and p $$-$$ $$bromophenolB)In$$ $$Reimer-Tiemann$$ reaction, on treating phenol with chloroform in the presence of sodium $$1$$ hydroxide, a $$-$$ CHO group is introduced at ortho position of benzene ring.$$C)$$ In Kolbe’s reaction it gives salicylic $$acidD)$$ On oxidation with $$K2Cr2O7+H2SO4$$ it gives a conjugated diketone

Question

Regarding phenol the correct statement $$areA)$$ It reacts with $$Br2/CS2$$  to give a mixture of $$o-bromophenol$$ and p $$-$$ $$bromophenolB)In$$ $$Reimer-Tiemann$$ reaction, on treating phenol with chloroform in the presence of sodium $$1$$ hydroxide, a $$-$$ CHO group is introduced at ortho position of benzene ring.$$C)$$ In Kolbe’s reaction it gives salicylic $$acidD)$$ On oxidation with   $$K2Cr2O7+H2SO4$$   it gives a conjugated diketone

Infinity Learn · Accepted Answer

Phenol reacts with bromine in $$CS2$$​ at low temperature to give o and $$p-bromophenol$$. In $$Reimer-Tiemann$$ reaction, on treating phenol with chloroform in the presence of sodium $$1$$ hydroxide, a $$-$$ CHO group is introduced at ortho position of benzene ring.Sodium phenoxide is generated by treating phenol with sodium hydroxide. It is treated with carbon dioxide to form $$ortho-hydroxy$$ benzoic $$acid(salicylic$$ $$acid)$$. The product formed when phenol is treated with acidified solution of $$Na2$$​$$Cr2$$​$$O7$$​ is benzoquinone a conjugated diketone. It is an oxidation reaction.

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