Regarding phenol the correct statement are
A) It reacts with ${Br}_{2} / {CS}_{2}$ to give a mixture of o-bromophenol and p - bromophenol
B)In Reimer-Tiemann reaction, on treating phenol with chloroform in the presence of sodium 1 hydroxide, a - CHO group is introduced at ortho position of benzene ring.
C) In Kolbe’s reaction it gives salicylic acid
D) On oxidation with $K_{2} {Cr}_{2} O_{7} + H_{2} {SO}_{4}$ it gives a conjugated diketone

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C,D only

B,C,D only

A,B,C,D

A,B,C only

answer is C.

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Detailed Solution

Phenol reacts with bromine in CS₂ at low temperature to give o and p-bromophenol.

In Reimer-Tiemann reaction, on treating phenol with chloroform in the presence of sodium 1 hydroxide, a - CHO group is introduced at ortho position of benzene ring.

Sodium phenoxide is generated by treating phenol with sodium hydroxide. It is treated with carbon dioxide to form ortho-hydroxy benzoic acid(salicylic acid).