Regarding phenol the correct statement are
A) It reacts with ${Br}_{2} / {CS}_{2}$ to give a mixture of o-bromophenol and p - bromophenol
B)In Reimer-Tiemann reaction, on treating phenol with chloroform in the presence of sodium 1 hydroxide, a - CHO group is introduced at ortho position of benzene ring.
C) In Kolbe’s reaction it gives salicylic acid
D) On oxidation with $K_{2} {Cr}_{2} O_{7} + H_{2} {SO}_{4}$ it gives a conjugated diketone

see full answer

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

C,D only

B,C,D only

A,B,C,D

A,B,C only

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Phenol reacts with bromine in CS₂ at low temperature to give o and p-bromophenol.

In Reimer-Tiemann reaction, on treating phenol with chloroform in the presence of sodium 1 hydroxide, a - CHO group is introduced at ortho position of benzene ring.

Sodium phenoxide is generated by treating phenol with sodium hydroxide. It is treated with carbon dioxide to form ortho-hydroxy benzoic acid(salicylic acid).

The product formed when phenol is treated with acidified solution of Na₂Cr₂O₇ is benzoquinone a conjugated diketone. It is an oxidation reaction.

Watch 3-min video & get full concept clarity