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Regarding the reaction ${2 FeCl}_{3} + H_{2} S \to {2 FeCl}_{2} + 2 HCl + S$ , the correct statement is:

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${FeCl}_{3}$ acts as an oxidising agent

${FeCl}_{3}$ is oxidised while $H_{2} S$ is reduced

$H_{2} S$ acts as an oxidising agent

Both $H_{2} S$ and ${FeCl}_{3}$ are oxidised

answer is A.

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Detailed Solution

The oxidation number of iron changes from +3 to +2. ${FeCl}_{3}$ is subsequently reduced and acts as an oxidizing agent.

Sulphur goes from an oxidation number of -2 to zero. $H_{2} S$ is consequently oxidized and serves as a reducing agent.

The reaction is as follows:
${2 FeCl}_{3} + H_{2} S \to {2 FeCl}_{2} + 2 HCl + S$

${FeCl}_{3}$ acts as an oxidising agent is the correct statement.

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