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Q.

Region I and II are separated by a spherical surface of radius 25 cm. An object is kept in region I at a distance of 40 cm from the surface. The distance of the image from the surface is :

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a

37.58 cm

b

9.52 cm

c

18.23 cm

d

55.44 cm

answer is D.

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Detailed Solution

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μ2v−μ1u=μ2−μ1R1.4v−1.25−40=1.4−1.25−25

1.4v=−0.1525−1.2540v=−37.58cm

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