Q.

Related to photoelectric effect, in Column I, some physical quantitative change while in Column II effect of these changes are given. Match the entries of Column I with the entries of Column II

 Column I Column II
I.Intensity of incident light changes keeping frequency same.a.Kmax of emitted photo-electrons changes
II.Frequency of incident light changesb.Stopping potential changes
III.Target material changesc.Saturation current changes
IV.KE of photoelectrons as they reach the collectord.

Time delay in emission of

photoelectrons changes

 

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a

ic ; iia,b ; iiia ; iva,d

b

ia,b ; iic ; iiia,b ; ivd

c

ic ; iia,b ; iiia,b ; ivd

d

ic ; iic,d ; iiia,b ; ivd

answer is C.

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Detailed Solution

If intensity changes, then number photons/time incident on the metal surface change and hence number of  photoelectrons liberated change, so saturation photocurrent changes. Stopping potential and Kmax  will remain the same

ii) From eV0=hfϕ  and  Kmax=hfϕ  If f changes, then V0  and  Kmax  change.

iii) FromeV0=hfϕ  and  Kmax=hfϕ  If target material changes, then ϕ  changes , thenV0  and  Kmaxchanges.

iv) If we change the potential difference between emitter and collector, then time taken for electrons to eject changes.

ic ; iia,b ; iiia,b ; ivd

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