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Q.

Relation between molarity (M) and mole fraction is ___?

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a

M=m×χAV×100

b

M=χB×1000×dχA.mA+χBmB

c

M=χA1dV

d

M=χA.1000×dχA.mA+χBmA

answer is B.

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Detailed Solution

Let ‘M’ be the molarity of solution and χA,χB be mole fractions of solvent and solute, respectively.

Suppose nA and nB moles of solvent and solute are mixed to form solution.

Mass of solution = nA×MA+nB×MB

where MA and MB are molar masses of solvent and solute, respectively.

Vsolution=massdensity=nAMB+nBMBd

Molarity, M=No. of moles of solute×1000volume of solution in ml

M=nB×1000×dnAMB+nBMB  divide both numerator and denominator withnA+nB

M=nBnA+nB×1000×dnAmAnA+nB+nBmBnA+nB=χB×1000×dχA.MA+χBMB

M=χB×1000×dχA.MA+χBMB

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