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Q.

Relation between voltage sensitivity $S_{V}$ and current sensitivity $S_{I}$ of a moving coil galvanometer is (given ‘G’ is the resistance of galvanometer)

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a

$S_{V} = {GS}_{I}$

b

$S_{V} S_{I} = G$

c

None

d

$S_{V} = \frac{S_{I}}{G}$

answer is B.

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Detailed Solution

$S_{I} = \frac{θ}{I} = \frac{N A B}{C}$

$S_{V} = \frac{θ}{V} = \frac{N A B}{G C}$

Thus, $S_{V} = \frac{S_{I}}{G}$

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