Q.

Relative decrease in vapor pressure of an aqueous solution containing 2 moles Cu(NH3)3Cl in 3 moles H2O is 0.50. On reaction with AgNO3,this solution will form

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a

2 mol AgCl

b

0.25 mol AgCl

c

0.5 mol AgCl

d

0.40 mol AgCl

answer is D.

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Detailed Solution

RLVP=Pp=insins+nO

0.5=i×2i×2+3

i + 1.5 = 2i 

i = 1.5

α=i-1n-1=1.5-12-1=0.51

So, 0.5 mole of AgCl.

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