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Relative density of silver is $10.8$ . The density of silver in the SI unit is

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10.8 \times 10^{5} kg m^{- 3}

10.8 \times 10^{3} kg m^{- 3}

10.8 \times 10^{4} kg m^{- 3}

10.8 \times 10^{- 3} kg m^{- 3}

answer is B.

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Detailed Solution

The density of silver in the SI unit is

10.8 \times 10^{3} kg m^{- 3}

.
As we know the density of water is

10^{3} kg m^{- 3}

Relative density of silver

= \frac{Density of silver}{Density of water}

Therefore density of silver

= Relative density of silver \times Density of water

So the density of silver is

= 10.8 \times 10^{3} kg m^{- 3}

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