Relative lowering of vapour pressure of non aqueous solution containing non volatile solute is 0.3. Molality of the solution will be ------(MW of solvent = 200)

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1.89 m

2.143 m

1.5 m

2.34 m

answer is C.

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Detailed Solution

$RLVP = X_{solute}; X_{solute} (n_{2}) = 0.3; X_{solvent} (n_{1}) = 0.7; Molality (m) = n_{solute} \times \frac{1000}{W_{solvent}}; Molality (m) = 0.3 \times \frac{1000}{0.7 (200)}; Molality (m) = 2.143 m;$

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