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Q.

Resistance of 0.1 M KCl solution in a conductance cell is 300 ohm and conductivity is 0.013 Scm-1. The value of cell constant is :

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a

3.9 m-1

b

39 cm-1

c

3.9 cm-1

d

None of these

answer is A.

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Detailed Solution

To determine the cell constant (denoted as K) of a conductance cell, we use the relationship between conductivity (κ), resistance (R), and the cell constant:

Formula: 

K = κ × R

Given Data:

  • Conductivity, κ = 0.013 S/cm
  • Resistance, R = 300 Ω

Conductivity is given as 0.013 S/cm. Convert it to S/m for consistency with SI units: 

0.013 S/cm = 1.3 S/m

Using the formula: 

K = κ × R 

Substitute the values: 

K = 1.3 S/m × 300 Ω = 390 m⁻¹

Since 1 m⁻¹ = 0.01 cm⁻¹, convert the result: 

K = 390 m⁻¹ × 0.01 = 3.9 cm⁻¹

Final Answer:

The cell constant is:  K = 3.9 cm⁻¹

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