Resistance of a conductivity cell (cell constant 129 ${\text{m}}^{-1}$ ) filled with 74.5 ppm solution of $KCl$ is $100 \Omega$ (labelled as solution 1). When the same cell is filled with $KCl$ solution of 149 ppm, the resistance is $50 \Omega$ (labelled as solution 2). The ratio of molar conductivity of solution 1 and solution 2 is i.e. $\frac{{\wedge }_1}{{\wedge }_2}=x\times {10}^{-3}.$ The value of $x$ is ___________. (Nearest integer) Given, molar mass of $KCl$ is $74.5 g{\text{mol}}^{-1}\text{.}$