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Q.

RH2  (ion exchange resin) can replace Ca2+ ions in hard water as RH2+Ca2+RCa+2H+.
If 1 L of hard water after passing through RH2haspH=3 then hardness in parts per million of Ca2+ is equal to

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answer is 20.

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Detailed Solution

[H+]=103M So [Ca2+]=12×103M wt.ofCa2+=1032×40
So, weight of Ca2+ ions in  mL hard water=12×103×40×106103=20

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