AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Right circular cylinder having diameter 12 cm and height 15 cm is full ice-cream. The ice- cream is to be filled in cones of height 12 cm and diameter 6 cm having a hemispherical shape on top. Find the number of such cones which can be filled with ice-cream.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given,
Diameter of right circular cylinder = 12 cm
Height of right circular cylinder = 15 cm
Cone height = 12 cm
Cone diameter = 6 cm
Radius of the cone = 3 cm
Number of ice-cream cones = N
C:UserssoftberryDownloadsP0041 JPEGQ.12.jpg

C:UserssoftberryDownloadsP0041 JPEGQ.12.jpg

Calculation
1st we have find the volume of circular cylinder

= π r^{2} h

= π \times 6 \times 6 \times 15 {cm}^{3}

2nd again find the volume of one ice-cream cone

= \frac{1}{3} π r^{2} h

= \frac{1}{3} \times π \times 3 \times 3 \times 12 {cm}^{3}

3rd find the volume of hemisphere of the cone

= \frac{2}{3} π r^{3}

= \frac{2}{3} \times π \times 3 \times 3 \times 3 {cm}^{3}

We have obtain the all required value. Put in the formula which is

Number of ice cream cones = \frac{volume of cylinder}{volume of cone + hemisphere}

N = \frac{π \times 6 \times 6 \times 15 {cm}^{3}}{\frac{1}{3} \times π \times 3 \times 3 \times 12 {cm}^{3} + \frac{2}{3} \times π \times 3 \times 3 \times 3 {cm}^{3}}

N = \frac{π \times 36 \times 15}{\frac{π}{3} \times (108 + 54)}

N = 10

Hence the number of cones = 10.
Correct option is 1.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!