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$ROH \overset{HCl}{\to} RCl$ ; the alkyl group -R in this reaction is

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All of these

-CH(CH₃)₂

-CHCH₃

-C(CH₃)₃

answer is C.

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Detailed Solution

1° alcohol and 2° alcohol require anhydrous ZnCl₂ along with HCl to form alkyl halides.

3° alcohols convert to 3° alkyl halides even in presence of HCl.

No doubt anhydrous ZnCl₂ can be used but not required.

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