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Q.

Roots of a quadratic equation x2+5x+3=0  are 4cos2α+a   and 4sin2α+a  . Another quadratic equation is given as x2+px+q=0 where p,qN  and  p,q[1,10]. If roots of second quadratic equation are real then the probability that they are 4cos4α+b and 4sin4α+b is 1k  where k =  
 

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answer is 16.

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Detailed Solution

For second equation to passes real roots 
D0

D=p24q

as p,q[1,10] and  p,qN
such 32 quadratics are possible
and x2+px+q=0 difference of roots =|4cos2α|  
so  p24q=2512

p24q=13
So (p,q) an be (5,3),(7,9)  two possible cases
So required probability  =232=116

 

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