Roots of $5x^2-6x-2=0$ are

Comparing $5x^2-6x-2=0$ with $a{x}^2+bx+c=0$, we get, a = 5, b = -6 & c = -2

$\mathrm{Therefore}, \mathrm{x} = \frac{-\mathrm{b}\pm \sqrt{{\mathrm{b}}^2-4\mathrm{ac}}}{2\mathrm{a}}$

$= \frac{-\left(-6\right)\pm \sqrt{{\left(-6\right)}^2-4\times 5\times -2}}{2\times 5}$

$=\frac{6\pm \sqrt{76}}{10}$

$=\frac{6\pm 2\sqrt{19}}{10}$

$=\frac{3\pm \sqrt{19}}{5}$

$\mathrm{x}=\frac{3-\sqrt{19}}{5} \mathrm{and} \mathrm{x}=\frac{3+\sqrt{19}}{5}$