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Roots of $x^{2} + 5 x + 6 = 0$ are

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-2, -3

2, -3

-2, 3

4, 2

answer is A.

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Detailed Solution

Note: The option that satisfies the given equation will be the correct option.

$x^{2} + 5 x + 6 = 0$ is given equation.

For x = -2, L.H.S = $(- 2)^{2} + 5 (- 2) + 6 = 4 - 10 + 6 = 0$ = R.H.S

For x = -3, L.H.S = $(- 3)^{2} + 5 (- 3) + 6 = 9 - 15 + 6 = 0$ = R.H.S

For x = 2, L.H.S = $(2)^{2} + 5 (2) + 6 = 4 + 10 + 6 = 20 \neq$ R.H.S

For x = 3, L.H.S = $(3)^{2} + 5 (3) + 6 = 9 + 15 + 6 = 30 \neq$ R.H.S

x = -2 & -3 both satisfy the given equation. Therefore, x = -2, -3 are roots of $x^{2} + 5 x + 6 = 0$

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