(S)-2-chloropentane undergoes nucleophilic substitution when treated with 1.5 M
NaOH solution, reaction follows the given rate law:
Rate = 2.35 x 10^-5[R - X ][^-OH] + 5.40 x 10^-6[R - X ]
Calculate percentage of retention product in product mixture.(Report in nearest integer)

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answer is 7.

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Detailed Solution

$\begin{array}{l} % {SN}^{1} = \frac{5.4 \times 10^{- 6} (R - X)}{(3.525 + 0.54) 10^{- 5} Rx} \times 100 \\ = \frac{0.54}{4.065} \times 100 = 13.28 % racemisation \\ % retention = \frac{13.28}{2} = 6.64 \approx 7 \end{array}$

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