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Q.

$S_{1} and S_{2}$ are two hollow concentric spheres enclosing charge $Q$ and $2 Q$ , respectively, as shown in figure. What is the ratio of the electric flux leaving through the surface of $S_{1} and S_{2}$ is $\frac{1}{K}$ . Then the value of K is

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answer is 3.

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Detailed Solution

The charge enclosed by S₁ is Q, so flux associated with it is $\frac{Q}{ε_{0}}$ .

The charge enclosed by S₂ is = 2Q + the charge enclosed by S₁ which is Q = 3Q

so flux associated with it is $\frac{3 Q}{ε_{0}}$ .

Therefore, the ratio is 1 : 3.

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S1 and S2 are two hollow concentric spheres enclosing charge Q and 2Q, respectively, as shown in figure. What is the ratio of the electric flux leaving through the surface of S1 and S2 is 1K. Then the value of K is