S1: Ar and Kr have same electron gain enthalpy valueS2: Rn is obtained as a decay product of R 226aS3: Boiling point of He is 4.2KCorrect statements from the given above

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S1: Ar and Kr have same electron gain enthalpy value

S2: Rn is obtained as a decay product of ${}^{226}R a$

S3: Boiling point of He is 4.2K

Correct statements from the given above

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S1 only

S2 and S3

S1, S2 and S3

S3 only

answer is C.

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Detailed Solution

Ar and Kr have same electron gain enthalpy value. Boiling point of He is 4.2 K (-268.95⁰C).

${}_{88}^{226}{Ra} \to {}_{86}^{222}{Rn} + {}_{2}^{4}{He}$

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