$S_2$ molecule in vapour state is paramagnetic due to the presence of unpaired electrons is

On applying MOT in $S_2$ molecule, we get,

${\mathrm{S}}_2\left(32{\mathrm{e}}^{-}\right)=\text{Same as }{\mathrm{O}}_2\left(16{\mathrm{e}}^{-}\right)=$ ${\sigma }_{1{\mathrm{ }\mathrm{s}}^2}^2<{\sigma }_{1\mathrm{ }\mathrm{s}}*2<{\sigma }_{2{\mathrm{ }\mathrm{s}}^2}^2<{\sigma }_{2\mathrm{ }\mathrm{s}}*2<\left({\pi }_{2\mathrm{px}}{}^2={\pi }_{2\mathrm{p}}{ }^2\right)<{\sigma }_2{}^2<\left({\pi }_{2\mathrm{px}}^{*1}={\pi }_{2\mathrm{p}}{{}^{*} }^1\right)$

So it is paramagnetic in nature due to the presence of unpaired electrons in Anti bonding ${\mathrm{\pi }}^{*}$ orbitals.