$S_{2} O_{3}^{- 2} \overset{H^{+}}{\to} {SO}_{4}^{- 2}$ . Equivalent weight of $S_{2} O_{3}^{- 2}$ ( M = Molar mass)

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$\frac{M}{4}$

$\frac{M}{2}$

$\frac{M}{8}$

answer is B.

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Detailed Solution

O.S of sulphur atom in thiosulphate ion and sulphate ion is +2 and +6 respectively.

n-factor = 2(6-2) = 8 ;

Alternatively

O.states of two sulphur atoms in thiosulphate ion are -2 and +6 whereas in sulphate ions both sulphur atoms have +6 state.

Thus change in O.S is -2 $\to$ +6 …change in O.S = 8 ;

n - factor = 8

Eq.wt = $\frac{M}{8}$

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