${\mathrm{S}}_8+8{\mathrm{O}}_2\to 8{\mathrm{SO}}_2,\Delta \mathrm{H}=-\mathrm{QK}$.

Then $\Delta \mathrm{E}$ for $\mathrm{S}+{\mathrm{O}}_2\to {\mathrm{SO}}_2$ is

 Chemical reaction

$\mathrm{S}+{\mathrm{O}}_2\to {\mathrm{SO}}_2$

 $\frac{1}{8}\times 8{\mathrm{SO}}_2⟶\frac{1}{8}{\mathrm{S}}_8+8{\mathrm{O}}_2\times \frac{1}{8}; \frac{\mathrm{\Delta H}}{8}$

$=-(-\frac{QkJ}{8})=+\frac{QkJ}{8}$

${\mathrm{SO}}_2⟶\frac{1}{8}{ \mathrm{S}}_8+{\mathrm{O}}_2 ;\mathrm{\Delta H}=+\frac{\mathrm{Q}}{8}\mathrm{kJ}$

${\mathrm{SO}}_2⟶{\mathrm{S}}_2{\mathrm{O}}_2 ;\mathrm{\Delta H}=+\frac{\mathrm{Q}}{8}\mathrm{kJ}$

Hence the correct answer is (D) $\frac{+Q}{8}$.