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Same amount of electric current is passed through solutions of AgNO₃and HCl. If 1.08 g of silver is obtained in the first case, the volume of hydrogen liberated at S.T.P. in the second case is

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112 cm³

22400 cm³

224 cm³

1.008 g

answer is A.

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Detailed Solution

$Number of equivalents of Ag = \frac{1.08}{108} = 0.01 eq . Since 1 eq . produces 11.2 L of H_{2} at STP . So, 0.01 eq . produces = 11.2 \times 0.01 L of H_{2} Volume of H_{2} = 0.112 L = 112 {cm}^{3}$

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