Same amount of electric current is passed through solutions of $AgN{O}_3$ and HCl. If 1.08 g of silver is obtained in the first case, the volume of hydrogen liberated at S.T.P. in the second case is

$$\begin{gathered} \mathrm{Ag} \mathrm{equivalents} \mathrm{in} \mathrm{number} = \left(\frac{1.08}{108}\right)=0.01 \\ \mathrm{As} 1 \mathrm{equals}, \mathrm{at} \mathrm{STP}, 11.2 \mathrm{litres} \mathrm{of} {\mathrm{H}}_2 \mathrm{are} \mathrm{produced}. \\ \mathrm{So} 0.01 \mathrm{eq}. \mathrm{generates} (11.2 \mathrm{x} 0.01) \mathrm{liters} \mathrm{of} {\mathrm{H}}_2 \\ \mathrm{Or} \mathrm{vol}=0.112 \mathrm{litre} =112{ \mathrm{cm}}^3 \end{gathered}$$

Therefore, the correct option is A