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Q.

Same amount of electricity is passed through the solutions of HCl and CuSO4. If 6.35 g of copper is deposited from CuSO4 solution, the amount of hydrogen liberated at STP will be

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a

0.1

b

1

c

0.01

d

0.001

answer is B.

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Detailed Solution

From Faraday's second law, 
                 wH2wCu=EH2ECu⇒wH2=163.5×6.35=0.1g
 

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