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Same current $i = 2 A$ is flowing in a wire frame as shown in figure. The frame is a combination of two equilateral triangles ACD and CDE of side $1 m$ . It is placed in uniform magnetic field $B = 4 T$ acting perpendicular to the plane of frame. The magnitude of magnetic force acting on the frame is

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$24 N$

$16 N$

$8 N$

Zero

answer is A.

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Detailed Solution

${\vec{F}}_{C A D} = {\vec{F}}_{C D} = {\vec{F}}_{C E D}$

Net force on frame $= 3 {\vec{F}}_{C D}$
$F = 3 (i l B) = (3) (2) (1) (4)$ $= 24 N$

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