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$S b C l_{3}$ and $B i C l_{3}$ on hydrolysis gives

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None of these

${Sb}^{+ 3} and {Bi}^{+ 3}$

$Sb (OH)_{3} and Bi (OH)_{3}$

$SbOCl and BiOCl$

answer is C.

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Detailed Solution

${SbCl}_{3} + H_{2} O \to SbOCl + 2 HCl$

$B i C l_{3} + H_{2} O ⟶ B i O C l + 2 H C l$

(Partial Hydrolysis)

The halides of $Sb$ and $Bi$ generate a partially hydrolyzed product as ionic character rises with falling group 15 reactivity.

Hence correct option C

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