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Q.

SbF5 reacts with XeF4 to form an adduct. The shapes of cation and anion in the adduct are respectively:

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a

Square planar, trigonal bipyramidal

b

T-shaped, octahedral

c

Square pyramidal, octahedral

d

Square planar, octahedral

answer is B.

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Detailed Solution

XeF4 is xenon tetrafluoride reacts with SbF5 [Lewis acid] to form an adduct. 

XeF4+SbF5XeF3+T-shape SbF6-octahedral

 XeF3+ is T-shaped and SbF6-is octahedral.

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