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Q.

S=[cot(logx)]5cosec2(logx)xdx(x>0) is equal to 

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a

112cotlogx12+C

b

16cotlogx6+C

c

16cotx6

d

116cotlogx16+C

answer is B.

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Detailed Solution

S=cot(logx)5cosec2(logx)xdx

logx=y

1xdx=dyS=(coty)5cosec2(y)dy

 Put coty=z

cosec2ydy=dzS=z5(dz)=z66+C=16(coty)6+CS=16(cot(logx))6+C

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