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$σ$ (screening constant) for Na and Na⁺ are respectively "x" and “y”. Then relation between them is

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x = y

x < y

x+y=0

x > y

answer is D.

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Detailed Solution

species	electronic configuration	screening constant
Na	(1s²)(2s²2p⁶)(3s¹)	$(2 \times 1) + (8 \times 0.85) + (0 \times 0.35) = 8.80$
Na⁺	(1s²)(2s²2p⁶)	$(2 \times 0.85) + (7 \times 0.35) = 4.15$

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