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$S e_{2} C l_{2}$ on disproportionation gives

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$S e_{2} C l_{2}$ and $S e C l_{4}$

$S e_{2} C l_{2}$ Only

$S e C l_{2} a n d S e$

$S e C l_{4} & S e$

answer is D.

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$2 S e_{2} C l_{2} \to S e C l_{4} + 3 S e$

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