sec0°+cot45°=1+1=2 OPTION: A sin45°=12 cosec45°=2 cosec245°=(2)2=2OPTION: B cos60°=12 sec60°=2OPTION: C sin30°=12 cosec30°=2 OPTION: D sec60°.tan45° =2.1=2

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$s e c 0 ° + c o t 45 ° =$

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$c o s e c^{2} 45 °$

$s e c 60 °$

$c o s e c 30 °$

$s e c 60 ° t a n 45 °$

answer is A.

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Detailed Solution

$\sec 0 ° + \cot 45 °$

$= 1 + 1$

$= 2$

OPTION: A

$\sin 45 ° = \frac{1}{\sqrt{2}}$

$\cos e c 45 ° = \sqrt{2}$

$\cos e c^{2} 45 ° = {(\sqrt{2})}^{2} = 2$

OPTION: B

$\cos 60 ° = \frac{1}{2}$

$\sec 60 ° = 2$

OPTION: C

$\sin 30 ° = \frac{1}{2}$

$\cos e c 30 ° = 2$

OPTION: D

$\sec 60 ° . \tan 45 °$

$= 2.1 = 2$

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