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Q.

$\sec (270 ° - θ) =$

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a

\cos e c θ

b

- \sec θ

c

- \cos e c θ

d

s e c θ

answer is C.

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Detailed Solution

In

Q_{3}, \sec θ

is negative

$270 °$ is odd multiple of $90 °$

$\sec (270 ° - θ) = - \cos e c θ$

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