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Second ionisation potential of oxygen is

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Equal to that of fluorine

Greater than that of fluorine

Less than that of fluorine

Half of that of fluorine

answer is C.

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Detailed Solution

Electronic configuration of $O$ = [He]2s²2p⁴

After removal of an electron, the configuration of O⁺ = [He]2s²2p³ (stable half filled configuration)

Electronic configuration of $F$ = [He]2s²2p5 (normal configuration)

Hence IP₂ of $O$ > F.

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