See the following flow chart.

 

  Which of the given data are not correct?

$44{\text{\hspace{0.17em}g\hspace{0.17em}of CO}}_{\text{2}}=1{\text{\hspace{0.17em}mole\hspace{0.17em}of\hspace{0.17em}CO}}_{\text{2}}=6.023\times {10}^{23}{\text{CO}}_{\text{2}}\text{molecules}$

At STP, 1 mole of any gas should occupy 22.4 L.

$\frac{22.4\text{\hspace{0.17em}L}}{44{\text{\hspace{0.17em}g\hspace{0.17em}of CO}}_{\text{2}}}\times 4.4{\text{\hspace{0.17em}g\hspace{0.17em}of CO}}_{\text{2}}\times \frac{1000\text{\hspace{0.17em}mL}}{1.0\text{\hspace{0.17em}L}}=2240{\text{\hspace{0.17em}mL\hspace{0.17em}of CO}}_{\text{2}}$

${\text{4.4 g of CO}}_{\text{2}}{\text{=\hspace{0.17em}0.1\hspace{0.17em}\hspace{0.17em}mol\hspace{0.17em}CO}}_{\text{2}}\times \frac{2\text{\hspace{0.17em}mol\hspace{0.17em}}\text{'}\text{O'}}{1{\text{\hspace{0.17em}mol\hspace{0.17em}CO}}_{\text{2}}}\times \frac{16\text{\hspace{0.17em}g.atoms}}{1\text{\hspace{0.17em}mol\hspace{0.17em}}\text{'}\text{O'}}=3.2\text{\hspace{0.17em}g\hspace{0.17em}atoms}$

 $4.4{\text{\hspace{0.17em}g\hspace{0.17em}of CO}}_{\text{2}}=\frac{1.0\text{\hspace{0.17em}mol}}{44{\text{\hspace{0.17em}g\hspace{0.17em}of CO}}_{\text{2}}}\times 4.4{\text{\hspace{0.17em}g\hspace{0.17em}of CO}}_{\text{2}}\times \frac{6.023\times {10}^{23}}{1.0\text{\hspace{0.17em}mol}}=6.023\times {10}^{22}$

Hence, option B , C are incorrect.