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Q.

Seeta Devi has Rs.9 in fifty paise and twenty-five paise coins. She has twice as many twenty-five paise coins as she has fifty paise coins. How many coins does she have?

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a

9

b

18

c

21

d

27

answer is D.

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Detailed Solution

Let us consider that she has ‘x’ number of coins of 50 paise and ‘y’ number of coins of 25 paise.
Amount of 50 paisa coins =

\frac{50}{100} \times x = 0.5 x

Amount of 50 paisa coins =

\frac{25}{100} \times y = 0.25 y

Given, total money she has is Rs.9
i.e., 0.5x + 0.25y = 9 …(i)
Also, she has twice as many twenty-five paise coins as she has fifty paise coins
i.e, y = 2x …(ii)
Put the value of y in eq(i), we get
0.5x + 0.25(2x) = 9
0.5x + 0.5x = 9
x = 9
y = 2(9) = 18
Hence, the total coins are 9 + 18 = 27
Therefore, 4 is the correct option.

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