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Seeta is moving due east with a velocity of $1 m/s$ and Geeta is moving due west with a velocity of $2 m/s$ . The velocity of seeta with respect of Geeta is

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$5 {ms}^{- 1} due east$

$3 {ms}^{- 1} due west$

$3 {ms}^{- 1} due east$

$5 {ms}^{- 1} due west$

answer is A.

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Detailed Solution

$v_{G} = - 2 \hat{i}$

$\vec{v_{sG}} = {\vec{v}}_{s} - {\vec{v}}_{G}$

$= 1 \hat{i} + 2 \hat{i}$

$= 3 \hat{i}$

$= 3 m/s due East$

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