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Blue solution of $Na$ in liq ${NH}_{3}$ . is unstable with respect to amide formation

${Na}_{2} O_{2}$ react with $CO$ and evolve $O_{2}$

${Li}^{+}$ does not form alum due to its high hydration energy

${NaNO}_{3}$ when heated at $800^{\circ} C$ produce two gases both are paramagnetic

answer is A.

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Detailed Solution

(i) ${Na}_{2} O_{2} + CO \to {Na}_{2} {CO}_{3}$
(ii) ${Li}^{+}$ does not form alum because of its small size.
(iii) ${NaNO}_{3} \to {NaNO}_{2} + \frac{1}{2} O_{2}$

${NaNO}_{2} \to {Na}_{2} O + N_{2} + \frac{3}{2} O_{2}$

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