Select correct statement(s) 

$\left(I\right)$ Mass of 1 mole glucose in amu= $\frac{180}{1.67\times {10}^{-24}}$

$\left(II\right)$ Mass of 1 molecule of glucose in gm $=\frac{180}{6.022\times {10}^{23}}$

$\left(III\right)$ Mass of 1 mole glucose in amu$=180\times 6.022\times {10}^{23}$

$\left(VI\right)$ Mass of 1 molecule of glucose in gm $=180\times 1.67\times {10}^{-24}$