Select correct statement(s) (I) Mass of 1 mole glucose in amu= 1801.67×10−24(II) Mass of 1 molecule of glucose in gm =1806.022×1023(III) Mass of 1 mole glucose in amu=180×6.022×1023(VI) Mass of 1 molecule of glucose in gm =180×1.67×10−24

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Select correct statement(s)

$(I)$ Mass of 1 mole glucose in amu= $\frac{180}{1.67 \times 10^{- 24}}$

$(I I)$ Mass of 1 molecule of glucose in gm $= \frac{180}{6.022 \times 10^{23}}$

$(I I I)$ Mass of 1 mole glucose in amu $= 180 \times 6.022 \times 10^{23}$

$(V I)$ Mass of 1 molecule of glucose in gm $= 180 \times 1.67 \times 10^{- 24}$

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answer is A.

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Detailed Solution

$\begin{array}{l} 1.67 \times 10^{- 24} gm = 1 amu \\ 1.67 \times 10^{- 24} \times N_{A} = 1 g \end{array}$

$\begin{array}{l} mass of 1 molecule of glucose = 180 amu \\ mass of 1 mole glucose = 180 gm \end{array}$

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