Select the correct order of $C - O$ bond length :

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$\begin{aligned} CO > Fe (CO)_{5} \end{aligned}$

$\begin{array}{r} [M (CO)_{4} {({PF}_{3})}_{2}] < [M (CO)_{5} ({PF}_{3})] \end{array}$

$\begin{array}{r} {CO}_{3}^{2 -} < CO \end{array}$

${[CO)_{6}]}^{-} > {[Ti (CO)_{6}]}^{2 -}$

answer is B.

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Detailed Solution

Correct order of bond length:
$\begin{array}{r} [M (CO)_{4} {({PF}_{3})}_{2}] < [M (CO)_{5} ({PF}_{3})] \end{array}$ ,
Synergic bond strength is lowest and bond length is greatest. As a result of the I effect of $F > Cl, {PF}_{3}$ has the lowest tendency to donate electron pair, followed by ${PCl}_{3}$ . So synergic bonding is greatest where the ${PF}_{3}$ ligand is present, and thus MCO bond strength and bond length are greatest.
So, option B is correct answer.