Select the correct statement about ${\mathrm{He}}_2$ and ${\mathrm{He}}_2^{+}$.

Electronic configuration of ${\mathrm{He}}_2^{+}$ is $1s^1{\sigma }^{\ast }1s^0$

Bond order will be $1-0/2=1/2$

Electronic configuration of ${\mathrm{H}}_2^{-}$ is $\sigma 1s^2{\sigma }^{\ast }1s^1$

Bond order will be $2-1/2=1/2$

Bond order for both ${\mathrm{He}}_2^{+}$ and ${\mathrm{H}}_2^{-}$ is same but ${\mathrm{He}}_2^{+}$ is more stable than ${\mathrm{H}}_2^{-}$ due to absence of electrons in anti-bonding orbital.